beanz Magazine

FizzBuzz

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It’s not as simple as it seems. Can you solve this classic programming problem?

Your challenge is to print out a list of numbers from 1 to 100. Every number divisible by 3 must be replaced by the word ‘fizz’, and every number divisible by 5 is replaced by ‘buzz’. If the number is divisible by both 3 and 5, then replace it with ‘fizzbuzz’.

It’s a simple problem with many solutions, from the quick and easy to the complex and elegant. In computer geek circles, ‘FizzBuzz’ is a classic puzzle that pops up time and time again. Companies even ask it to candidates during coding interviews!

Take a moment and think about how you’d approach the code. What hurdles could you hit? What coding structures can you pull out of your arsenal?

A SIMPLE SOLUTION

The piece of code that makes things simple is the modulus operator, which you write as “%” and say out loud as “mod”. It’s a mathematical operator, like +, -, or *, and it tells us how much is leftover after a division.

Remember how we did divisions before learning about decimal numbers? So if:

15 / 6 == 2 (with a of remainder 3)
THEN
15 % 6 == 3

 

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Links from the bottom of all the February 2019 articles, collected in one place for you to print, share, or bookmark.

Interesting stories about science and technology for February 2019.